javascript - Putting elements in an array? -



javascript - Putting elements in an array? -

i have question. i'll post html first, know shouldn't utilize tables designing , stuff that. it's learning purposes only.

<table id="placeholder"> <tr> <td><img src="img/1.jpg"/></td> <td><img src="img/2.jpg"/></td> <td><img src="img/3.jpg"/></td> </tr> <tr> <td><img src="img/4.jpg"/></td> <td><img src="img/5.jpg"/></td> <td><img src="img/6.jpg"/></td> </tr> <tr> <td><img src="img/7.jpg"/></td> <td><img src="img/8.jpg"/></td> <td><img src="img/9.jpg"/></td> </tr> <tr> <td><img src="img/10.jpg"/></td> <td><img src="img/11.jpg"/></td> <td><img src="img/12.jpg"/></td> </tr> <tr> <td><img src="img/10.jpg"/></td> <td><img src="img/11.jpg"/></td> <td><img src="img/12.jpg"/></td> </tr> </table>

is possible set img's in array? way can fadeout images want. allow want rid of 5th images, can like: images[4].fadeout("slow"); or that. possible this? or there improve way this? i've tried var images = $('td > img'); didn't work (or i'm doing wrong). i'm searching net ways it, haven't found yet help me. might? in advance!

you can select images with

var $images = $('#placeholder img');

if want select specific image, can utilize .eq() [docs]:

$images.eq(4).fadeout();

$images[4] works too, not homecoming jquery object, corresponding dom element. hence cannot phone call fadeout on directly.

without jquery, can images getelementsbytagname [docs]:

var images = document.getelementbyid('placeholder').getelementsbytagname('img');

this gives array (actually nodelist) of dom elements , 1 time again cannot straight phone call jquery method fadeout on them.

javascript jquery arrays

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