python - Scapy get the actual value of a field -



python - Scapy get the actual value of a field -

this question related this other one

i check value of field in scapy:

def compute(fields): print fields print fields[1].name print fields[1].size print fields[1].default homecoming 23 class foo(packet): array=[ bitfield("foo",0x0,2), bitfield("foo1",0x0,2), bitfield("bar",0x0,2), bitfield("blub",none,2) ] def post_build(self, p, pay): print dir(self.array[1]) res = compute(self.array) p = struct.pack(">b", res) homecoming p if __name__ == "__main__": interact(mydict=globals(), mybanner="")

the code not entirly working, of import parts are. output is:

[<field ().foo>, <field ().foo1>, <field ().bar>, <field ().blub>] foo1 2 0

now, problem when alter value on commandline:

>>> a=foo() >>> a.foo1=0x23 >>> a.show2()

how can find out (in compute method) value foo1 has? think not hard question, cannot figure out i'm missing here :/ cool if give me hand :)

with best regards

from command line (or in code declare scapy layer) access scapy layer , field so:

>>> a=foo() >>> a[foo].foo1 = 0x23

does reply question? if not, explain purpose of compute() function , edit answer.

python scapy

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